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Requires creation of a second list, and a second traversal through the (large) main list.It also has the added disadvantage of going through each combination twice (for example, once as [A, B] and another time as [B, A]), even when B was "removed".Either you define the pairs to be directional, (A, B) != (B, A), or you remove both A and B when the condition is satisfied. I am looking for a somewhat generic answer assuming unidirectional groups, as I've faced this problem multiple times.

As an example, let's assume I have the logic cubes (of 2 inputs each) A=X1, B=11 and C=00.In technical terms, a logic cube is an n-input, 1-output Programmable Logic Array (PLA) description.For memory reasons (as we often have thousands of cubes, each with hundreds of inputs), they use a custom collection implementation where each entry uses 2 bits in a vector of longs (very similar to the Java Bit Set implementation).Then you could do it with two "iterators" because the Singly Linked List itself is the iterator.I suspect there is no such implementation in Java because this type of list naturally pushes you in a tail recursive direction, which isn't properly optimized in Java.

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But I can't be certain one doesn't exist, so I've actually never even tested this out.

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